![evoland 2 fragment of time evoland 2 fragment of time](https://i1.wp.com/ivasoundstudio.com/wp-content/uploads/2021/05/dofus-miniature-42.png)
Why, Okay, And now we want Teoh we see here that are C 16 age 14 our compound. Okay, And now that we have, um, r c 16 age, 1400 carbon. And so that's going to look something like this. Both of the hydrogen and both of our bro minds are going to leave, and we're going to get the formation of to Al Keene's. Okay, so this I'm gonna say this is our compound, Compound X, and so when we treat it with the base, we're going Teoh de protein A. Um, we should be able to easily see the products for that. So now that we have figured out our compound X, we're going to go ahead and treat it with a strong base and we're going to get our two eliminations reactions that are going to occur. And so we're likely going to say that this is not going to be our Compound X right. Or, you know, for the right bromide we could have this hydrogen or we're gonna have decided, and we'll have a lot of competing elimination reactions. We also have this side region which could react with the left bromide. But if we let the right compound here, there's a lot of competing elimination reactions that can occur right, cause we have, you know, we have you have this hydrogen which can react with the left bromide. Therefore, this is likely going to be our, um desired Compound X right. And because the only hydrogen is that we can, um, that we have as our beta hydrogen zehr going to be this one for, ah, the left bromide and this one for the right bromide. Right? But if we look at this here, um, so since we have our bromide in the one and four position here that we are going to have to elimination reactions that occur. And so, um, we know that Ah, see, 16 age 14 is going to be our only product. So, um, we know that since we're getting rid of two hydrogen into bromides, we must have had two eliminations that occurred, right? So from here, I'm gonna say to Ellen, reactions occurred, okay. So how do we know which one we have? Um well, we look at the following piece of information that we're giving, right? So when do you treat it with strong pace? We're gonna get compound. And now we see once again, we have our plane, a cemetery, and our compound is going to be optically inert. So we're going to get this here and now our our bromides and hydrogen Cuadrado's in here.
![evoland 2 fragment of time evoland 2 fragment of time](https://i.ytimg.com/vi/6YZYnaU97T4/maxresdefault.jpg)
You can draw this in another way as well, Right? So with our bromides on the carbon number two So what is that going to look like? Right. And so therefore, we're going to have an optically inert compound that fulfills the requirement liquid formula. Here we have our plane of symmetry, right? here. Okay, And this is very easy to see our plane of symmetry. Like I said earlier, we're gonna have a R r bromides on the one and four carbon here. I'm gonna draw in a certain way just so we can really see here the fact that we have ah, plainer, uh, planner cemetery, and therefore our compound is going to be miso here. So why don't we go ahead and start drawing that now? Um, all right, so given that information, we can draw in the following way, So we know we're going to have our are two fellow rings here. Ah, so carbon one and four or it's got to be on carbon two or three in order to fulfill this. And therefore, um, so are br to in order for it to be a miso compound and optically inert, it's either got to be on. Carbon Jane are four carbon parent chain. And now we have our BR to and so this is going to suggest, um if we have to federal rinks, we're going to have a four. So it's likely that, um, since we have armies of compound, I'm going to say we're going to have to, uh, fennel rinks, likely right. And so, um, were also given the molecular formula, we have C 16 age 16 br to, um so the fact that we have R C 16 80 16 it's going to suggest that we're going to probably have aromatic hydrocarbons. So are our compound is going to be a Cairo, although it's likely that it's going to have Kyrill centers. So with Compound X, we know that it is optically inert on so optically inert means to believe means that we're going to have a plane of symmetry in our compound, and this is indicative of ah, miso compound. But it does require us to take to kind of analyze the pieces of information that we're given, um, one at a time. So we see this a pretty difficult question. So we're giving the following information here and for three different compounds X, y and Z, and we want to try to figure out structures for each of these compounds with the following information.